Is the Heat Equation Model for an Insulated Rod Correct?

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dirk_mec1
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Homework Statement



http://img444.imageshack.us/img444/7641/20240456gw8.png

Homework Equations


http://img14.imageshack.us/img14/5879/63445047rj2.png

Note that the rightside of the rod is insulated.

The Attempt at a Solution


I get this model:

[tex]\frac{ \partial{u} }{ \partial{t} } = \kappa \frac{ \partial{ ^2 u} }{ \partial{x^2} } +s[/tex]

[tex]u(0,t)=u_0[/tex]
[tex]\frac{ \partial{u}} { \partial{x} } = 0[/tex]In steady state this gives: [tex]u(x) = \frac{- s}{ \kappa} \frac{1}{2}x^2 + \frac{s}{ \kappa } L x + u_0[/tex]

But if I calcute than the asked u' at x=0:

I get:

[tex]\frac{du}{dx} = \frac{s}{ \kappa} L[/tex]

Is this correct?
 
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What I don't understand is what do they mean by "total heat supply"? I presume they mean s (=source). But I get a different answer out of my equation.
 
Your answer looks fine. Note, though, that the equation

[tex] \frac{ \partial{u}} { \partial{x} } = 0[/tex]

means nothing on its own; we need to specify a location:

[tex] \left(\frac{ \partial{u}} { \partial{x} }\right)_{x=L} = 0[/tex]

For the heat supply question: we need to distinguish the total heat S from the heat per length [itex]s=S/L[/itex] that goes into the differential equation. By applying Fourier's conduction law, your answer indicates a total heat flow of [itex]sL=S[/itex], which is correct. The units will always confirm whether S or s is being used appropriately.
 
Mapes said:
Your answer looks fine. Note, though, that the equation

[tex] \frac{ \partial{u}} { \partial{x} } = 0[/tex]

means nothing on its own; we need to specify a location:

[tex] \left(\frac{ \partial{u}} { \partial{x} }\right)_{x=L} = 0[/tex]
You're right but I couldn't get this in latex. Note that the notation you are using isn't the right one either there should be a large bar at the right hand side something like this: [tex]|_{x=L}[/tex]

For the heat supply question: we need to distinguish the total heat S from the heat per length [itex]s=S/L[/itex] that goes into the differential equation. By applying Fourier's conduction law, your answer indicates a total heat flow of [itex]sL=S[/itex], which is correct. The units will always confirm whether S or s is being used appropriately.
Of ocurse, how could I overlooked that!