Is the Kinematic Equation Applicable for Calculating Projectile Motion Speed?

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The discussion focuses on calculating the speed of water just before it hits a building after being shot from a hose at an angle. The initial speed of the water is 27.5 m/s, and the water travels 51.81 m in 3.00 seconds. The kinematic equation Vf² = Vyi² + 2(ay)(Δy) was used, but initial calculations yielded incorrect results due to arithmetic errors. After correcting the vertical component of velocity, the calculations aligned with the expected outcome. The final speed can be accurately determined by combining the horizontal and vertical components as vectors.
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Homework Statement



Firemen are shooting a stream of water at a burning building using a high-pressure hose that shoots out the water with a speed of 27.5 m/s as it leaves the end of the hose. Once it leaves the hose, the water moves in projectile motion. The firemen adjust the angle of elevation Θ of the hose until the water takes 3.00 s to reach a building 51.81 m away. You can ignore air resistance; assume that the end of the hose is at ground level.

How fast is it moving just before it hits the building?

Θ=51.1

Homework Equations



The equation i used to solve it was V=sqrt(vx2+vy2) and the answer was found to be 19.0 m/s

i was wondering if this equation would work to solve it? i can't get it to come out with 19 m/s though.

Vf2= Vyi2+2(ay)(Δy)

The Attempt at a Solution



Vf2= Vyi2+2(ay)(Δy)

so with this equation i used Vyi to be 27.5sin(51.1)=21.01

i used ay to be -9.8

i used Δy to be 27.5sin(51.1)(3) + .5(-9.8)(32) = 20.11 - 0 = 20.11
(the minus 0 is because of the final height minus the initial height).Vf2= Vyi2+2(ay)(Δy)

Vf = 6.87 which is definitely wrong.

Anyone know why this equation doesn't work using these numbers i calculated?

Any suggestions. Thanks :)
 
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mybrohshi5 said:
i was wondering if this equation would work to solve it? i can't get it to come out with 19 m/s though.

Vf2= Vyi2+2(ay)(Δy)
That will find Vyf, not the complete Vf. You still need to add Vx to get the total V.
 
if i add that to the Vx then that comes out to be 24.14 m/s which is also not the correct answer.

6.87 + 27.5cos(51.1) = 24.14 m/s
 
mybrohshi5 said:
if i add that to the Vx then that comes out to be 24.14 m/s which is also not the correct answer.

6.87 + 27.5cos(51.1) = 24.14 m/s
These are vector components. When I said 'add' I meant combine them like vectors:
mybrohshi5 said:
V=sqrt(vx2+vy2)
 
oh i see what you are saying.

well i did that and its still a little under

sqrt(17.27^2 + 6.87^2) = 18.58 :(

i guess this way may just not work.

Thank you for your help and explanations.
 
mybrohshi5 said:
i guess this way may just not work.
It should work just fine. Check your arithmetic. For example, this calculation is not quite right:
mybrohshi5 said:
so with this equation i used Vyi to be 27.5sin(51.1)=21.01
 
thank you. with that new number of 21.4 it works out correctly.

thank you for catching that error and all of your time and help :)
 

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