What is the velocity of the projectile when it hits the net?

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SUMMARY

The projectile, The Great Projecto, is launched from a cannon at a velocity of 29.8 m/s and an angle of 50.4 degrees, landing in a net positioned 2.0 m above the launch elevation. To determine the velocity upon impact with the net, the horizontal component (vx) remains constant at 36.02 m/s, while the vertical component (vy) must be calculated using the kinematic equations. The acceleration due to gravity is -9.8 m/s², which affects the vertical motion. The final velocity when hitting the net can be derived from these components.

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gungo
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Homework Statement


The Great Projecto is fired from a cannon at a velocity of 29.8 m/s at an angle of 50.4 degrees. He lands in a net which is 2.0 m above his starting elevation. What is his velocity when he hits the net? How do I find it with no starting elevation?
vx1: 36.02 m/s vy1: 19.0 m/s
vy2=?
vx2: 36.02 m/s a= -9.8/ms
a=0

Homework Equations


The Attempt at a Solution

 
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Hi gungo, Welcome to Physics Forums.

You need to make an attempt at solution in the indicated area of the template. Even if you can't solve the problem completely or correctly, you should at least be able to write down relevant equations for this type of problem.

If you look carefully at the problem statement you will see that he lands 2.0 meters above his starting elevation. So pick any starting elevation you like.
 
gungo said:
at a velocity of 29.8 m/s
gungo said:
vx1: 36.02 m/s
The magnitude of one component of velocity cannot exceed the magnitude of the overall velocity.
 

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