Is the Kinematic Equation Applicable for Calculating Projectile Motion Speed?

  • Thread starter Thread starter mybrohshi5
  • Start date Start date
  • Tags Tags
    Formula
Click For Summary

Homework Help Overview

The discussion revolves around the application of kinematic equations to analyze projectile motion, specifically in the context of water being shot from a hose at an angle towards a building. The original poster is trying to determine the speed of the water just before it hits the building after a specified time and distance.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss the use of the kinematic equation Vf² = Vyi² + 2(ay)(Δy) to find the final speed of the projectile. There are questions about the correctness of the calculations and the interpretation of vector components in determining the total speed.

Discussion Status

Some participants have offered guidance on combining vector components to find the resultant speed. There is an ongoing exploration of the calculations, with participants checking each other's arithmetic and discussing the implications of their findings.

Contextual Notes

Participants are working under the assumption that air resistance can be ignored and that the initial height of the water is at ground level. There is a specific focus on the angle of elevation and its impact on the calculations.

mybrohshi5
Messages
365
Reaction score
0

Homework Statement



Firemen are shooting a stream of water at a burning building using a high-pressure hose that shoots out the water with a speed of 27.5 m/s as it leaves the end of the hose. Once it leaves the hose, the water moves in projectile motion. The firemen adjust the angle of elevation Θ of the hose until the water takes 3.00 s to reach a building 51.81 m away. You can ignore air resistance; assume that the end of the hose is at ground level.

How fast is it moving just before it hits the building?

Θ=51.1

Homework Equations



The equation i used to solve it was V=sqrt(vx2+vy2) and the answer was found to be 19.0 m/s

i was wondering if this equation would work to solve it? i can't get it to come out with 19 m/s though.

Vf2= Vyi2+2(ay)(Δy)

The Attempt at a Solution



Vf2= Vyi2+2(ay)(Δy)

so with this equation i used Vyi to be 27.5sin(51.1)=21.01

i used ay to be -9.8

i used Δy to be 27.5sin(51.1)(3) + .5(-9.8)(32) = 20.11 - 0 = 20.11
(the minus 0 is because of the final height minus the initial height).Vf2= Vyi2+2(ay)(Δy)

Vf = 6.87 which is definitely wrong.

Anyone know why this equation doesn't work using these numbers i calculated?

Any suggestions. Thanks :)
 
Physics news on Phys.org
mybrohshi5 said:
i was wondering if this equation would work to solve it? i can't get it to come out with 19 m/s though.

Vf2= Vyi2+2(ay)(Δy)
That will find Vyf, not the complete Vf. You still need to add Vx to get the total V.
 
if i add that to the Vx then that comes out to be 24.14 m/s which is also not the correct answer.

6.87 + 27.5cos(51.1) = 24.14 m/s
 
mybrohshi5 said:
if i add that to the Vx then that comes out to be 24.14 m/s which is also not the correct answer.

6.87 + 27.5cos(51.1) = 24.14 m/s
These are vector components. When I said 'add' I meant combine them like vectors:
mybrohshi5 said:
V=sqrt(vx2+vy2)
 
oh i see what you are saying.

well i did that and its still a little under

sqrt(17.27^2 + 6.87^2) = 18.58 :(

i guess this way may just not work.

Thank you for your help and explanations.
 
mybrohshi5 said:
i guess this way may just not work.
It should work just fine. Check your arithmetic. For example, this calculation is not quite right:
mybrohshi5 said:
so with this equation i used Vyi to be 27.5sin(51.1)=21.01
 
thank you. with that new number of 21.4 it works out correctly.

thank you for catching that error and all of your time and help :)
 

Similar threads

Replies
16
Views
3K
  • · Replies 14 ·
Replies
14
Views
4K
  • · Replies 4 ·
Replies
4
Views
3K
  • · Replies 2 ·
Replies
2
Views
4K
  • · Replies 2 ·
Replies
2
Views
2K
Replies
1
Views
20K
Replies
8
Views
2K
  • · Replies 8 ·
Replies
8
Views
4K
  • · Replies 6 ·
Replies
6
Views
8K
Replies
4
Views
15K