Is the Mandelbrot Set Lebesgue Measurable?

Dragonfall
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What is the Lebesgue measure of the Mandelbrot set?
 
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Is it known?
 
The mandelbrot set is not "Lebesque measurable". Is is possible that you are referring to the dimension of the set?
 
According to Wikipedia, the measure is estimated to be 1.506 591 77 ± 0.000 000 08, and it is conjectured to be exactly \sqrt{6\pi-1} - e

edit: But after reading the source... I'm really not sure if I would trust that too well. However, the two large areas of the Mandelbrot set each definitely have positive measures
 
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How do you know that it's not Lebesgue measurable?
 
HallsofIvy said:
The mandelbrot set is not "Lebesque measurable". Is is possible that you are referring to the dimension of the set?

<< insult deleted by Mentors >> every closed set is Lebesgue measurable.

The Mandelbrot Set is closed.

J
 
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Dragonfall said:
How do you know that it's not Lebesgue measurable?

I know this is a very old post, but read what I just posted in reply.

J
 

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