MHB Is the Slope of the Line Passing Through the Given Points Equal to 2x + h?

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The discussion centers on demonstrating that the slope of the line through the points (x, x^2) and (x + h, (x + h)^2) equals 2x + h. The slope is calculated using the formula m = [(x + h)^2 - x^2] / (x + h - x). Through algebraic manipulation, it is shown that both sides of the equation simplify to 2x + h. The conclusion confirms that the initial assumption about the slope being equal to 2x + h is correct. The proof is successfully completed.
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Show that the slope of the line passing through the points
(x, x^2) and (x + h, (x + h)^2) is 2x + h.

Let m = slope

The slope m is given to be 2x + h.

2x + h = [(x + h)^2 - x^2)/(x + h - x)]

I must show that the right side = the left side.

Correct?
 
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Let's assume that it is not correct. Where is the error?
 
greg1313 said:
Let's assume that it is not correct. Where is the error?

I do not understand.
 
2x + h = {x+h}^{2} - {x}^{2}/(x + h - x)

2x + h = (x + h)(x + h) - {x}^{2}/h

2x + h = {x}^{2} + 2xh + {h}^{2} - {x}^{2}/h

2x + h = 2xh + {h}^{2}/h

2x + h = 2x + h

Done!
 
Here is a little puzzle from the book 100 Geometric Games by Pierre Berloquin. The side of a small square is one meter long and the side of a larger square one and a half meters long. One vertex of the large square is at the center of the small square. The side of the large square cuts two sides of the small square into one- third parts and two-thirds parts. What is the area where the squares overlap?

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