Is the symbol dx equivalent to Δx in these situations?

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The symbols Δx and dx represent different concepts in mathematics and physics. Δx denotes a finite change in position (xfinal - xinitial), while dx signifies an infinitesimal change. In the context of speed, both v = Δx/Δt and v = dx/dt can be correct under specific conditions, such as when acceleration is absent. However, dx/dt is preferred for its precision, while Δx/Δt requires clarification of the interval used. Understanding these distinctions is crucial for accurately interpreting equations in differential calculus and physics.
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I have seen the symbol dx in differential equations, but recently I saw it appear in various other equations that I previously thought included Δx instead of dx.

Are those two symbols the same? I mean, is Δx = dx = xfinal - xinitial ?

This may be the wrong thread, but I am still a newcomer, and plus I thought I saw another such question around here before!

Thanks
 
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karkas said:
I have seen the symbol dx in differential equations, but recently I saw it appear in various other equations that I previously thought included Δx instead of dx.

Are those two symbols the same? I mean, is Δx = dx = xfinal - xinitial ?

Hi karkas! Welcome to PF! :smile:

∆x is an actual difference.

dx is an infinitesimal difference.

dx/dt = lim{∆x(t)/∆t} = lim{[x(t+∆t) - x(t)]/∆t}.

(for linear functions, of course, it makes no difference)

So Δx = xfinal - xinitial is correct :smile:

but dx = xfinal - xinitial is wrong :cry:
 
Thanks Tiny - tim!

Yet I still don't understand something (probably it's because we're taught everything in Greek and I am still not adept with English terminology).

If I say that the speed is v = Δx/Δt and v = dx/dt is the same thing if there is no force disrupting the linear movement?
 
karkas said:
Thanks Tiny - tim!

Yet I still don't understand something (probably it's because we're taught everything in Greek and I am still not adept with English terminology).

If I say that the speed is v = Δx/Δt and v = dx/dt is the same thing if there is no force disrupting the linear movement?

hmm … mathematical symbols should be an international language! :smile:

Yes, v = dx/dt is always correct …

but if there's no acceleration, then v = ∆x/∆t is also correct.

However, when you write dx/dt, you don't need to explain it,

but when you write ∆x/∆t, you need to specify a particular interval. :wink:
 
In physics and engineering, cap delta is frequently used to denote a finite change, a little bit of something. Thus cap delta x denotes a finite change in x.

It is common in setting up a problem to write things in terms of finite differences before passing to the limit when these differences, in the form of ratios, become derivatives.
 
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