- #1

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In summary, the system is nonlinear if a scalar multiple of the force does not lead to a scalar multiple of the mass.f

- #1

- 37

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- #2

Mentor

- 36,486

- 13,597

Linear in which variable?

Can you add some context to your question?

Can you add some context to your question?

- #3

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- #4

Mentor

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y and x have a linear relationship - if you multiply x by 2, y gets multiplied by 2 as well. The system is linear, if you consider "a" as a constant parameter, and look at x and y. You can add multiple solutions as superpositions.

y and a do not have a linear relationship - if you multiply a by 2, y gets multiplied by 4. The system is not linear, if you consider "x" as a constant parameter, and look at a and y. You cannot add multiple solutions as superposition.

- #5

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[itex] f - mg - u = 0 [/itex] where f is the input and u is a disturbance (both are functions of time).

having a scalar multiple of my force would not increase the system's response in a linear way. does this mean that this system is not linear?

[itex] f(a*t) - mg - u(t) = 0 [/itex]

- #6

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- #7

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- #8

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I think it is non-linear with the interpretation as in post #5.

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