Is the System of ODEs Defined by Matrix B Decoupled?

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Given the matrix b=\begin{pmatrix}-1&0&-1\\-4&3&-1\\0&0&-2\end{pmatrix} decide if the system of ODEs, \frac{dx}{dt}=Bx is decoupled. If yes find the general solution x=xh(t)

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The Attempt at a Solution


I would say the matrix is decoupled since the second equation involving 2x2(t) can be solved without the other two equations. Then the third equation can be solved without knowing x1(t). We have:
<br /> x&#039;_1 = -x_1 - x_3 \\ <br /> x&#039;_2 = -4x_1 + 3x_2 - x_3 \\ <br /> x&#039;_3 = -2x_3<br />
Im not sure where to go from here.
 
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You may want to look into matrix diagonalization [1]. If B can written as A D A-1, where D is a diagonal matrix, can you then use this to rewrite you ODE system to a new uncoupled variable basis?

[1] http://en.wikipedia.org/wiki/Diagonalizable_matrix
 
I have found the diagonal matrix,
D=<br /> \begin{pmatrix}<br /> -1 &amp; 0 &amp; 0\\<br /> 0 &amp; 3 &amp; 0\\<br /> 0 &amp; 0 &amp; -2<br /> \end{pmatrix}<br />
I thought the matrix B was already uncoupled though. Is this not the case?
 
jimmycricket said:
Given the matrix b=\begin{pmatrix}-1&amp;0&amp;-1\\-4&amp;3&amp;-1\\0&amp;0&amp;-2\end{pmatrix} decide if the system of ODEs, \frac{dx}{dt}=Bx is decoupled. If yes find the general solution x=xh(t)

Homework Equations





The Attempt at a Solution


I would say the matrix is decoupled since the second equation involving 2x2(t) can be solved without the other two equations.
?
Do you mean the third equation? It involves only x3' and x3.
jimmycricket said:
Then the third equation can be solved without knowing x1(t). We have:
<br /> x&#039;_1 = -x_1 - x_3 \\ <br /> x&#039;_2 = -4x_1 + 3x_2 - x_3 \\ <br /> x&#039;_3 = -2x_3<br />
Im not sure where to go from here.

jimmycricket said:
I have found the diagonal matrix,
D=<br /> \begin{pmatrix}<br /> -1 &amp; 0 &amp; 0\\<br /> 0 &amp; 3 &amp; 0\\<br /> 0 &amp; 0 &amp; -2<br /> \end{pmatrix}<br />
I thought the matrix B was already uncoupled though. Is this not the case?
The system of equations was not uncoupled. The purpose of finding a diagonal matrix that is similar to B gives you a system that is uncoupled. In an uncoupled system, each equation involves only a single variable and its derivative.
 
That was an error on my part, what I meant was the matrix is decoupled since the second equation involving -2x_3(t) can be solved without the other two equations and then we can solve for x_1(t) without knowing x_2(t)
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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