Is the system uniquely solvable?

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The discussion centers on the uniqueness of solutions for the system of equations $$x^3+y^3+z^3=1$$ and $$x\cdot y\cdot z=-1$$ in the neighborhood of the point $(1, -1, 1)$. Participants clarify that the point $(1, 1, 1)$ is not valid for this system, and the correct point of interest is $(1, -1, 1)$. The implicit function theorem is suggested as a method to determine the uniqueness of the solutions for the variables $y$ and $z$ in terms of $x$.

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mathmari
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Hey! :o

Is the system $$x^3+y^3+z^3=1 \\ x\cdot y\cdot z=-1$$ in a region of the point $(1; 1; 1)$ uniquely solvable for $y = y (x) $ and $z = z (x)$ ?

How can we check that? Could you give me a hint? (Wondering)
 
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mathmari said:
Hey! :o

Is the system $$x^3+y^3+z^3=1 \\ x\cdot y\cdot z=-1$$ in a region of the point $(1; 1; 1)$ uniquely solvable for $y = y (x) $ and $z = z (x)$ ?

How can we check that? Could you give me a hint? (Wondering)
The point $(1,1,1)$ does not lie on either of those surfaces. Did you mean the point $(-1,1,1)$?
 
Opalg said:
The point $(1,1,1)$ does not lie on either of those surfaces. Did you mean the point $(-1,1,1)$?

Oh I meant $(1;-1;1)$. (Tmi)
 
mathmari said:
Hey! :o

Is the system $$x^3+y^3+z^3=1 \\ x\cdot y\cdot z=-1$$ in a region of the point $(1; 1; 1)$ uniquely solvable for $y = y (x) $ and $z = z (x)$ ?

How can we check that? Could you give me a hint? (Wondering)

If by "region" you mean "neighbourhood", then my hint would be to use the implicit function theorem.
 

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