Is there a formula for combining heat capacities of liquids and gases?

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SUMMARY

This discussion focuses on the formulation of heat capacities for a mixture of liquids and gases, specifically water, oil, and natural gas. The participants propose an equation for calculating the overall heat capacity of a system at thermal equilibrium, incorporating the specific heat capacities of each component. The final recommended formula is CpTotal = (Wo/WTotal)*Cpo + (Ww/WTotal)*Cpw + (Wg/WTotal)*Cpg, where Wo, Ww, and Wg represent the mass of oil, water, and gas respectively. The importance of ensuring consistent units across all components is emphasized to achieve meaningful results.

PREREQUISITES
  • Understanding of specific heat capacity (Cp) and its units (kJ/kg.K)
  • Knowledge of mass flow rate calculations for different phases
  • Familiarity with the concept of thermal equilibrium in multi-phase systems
  • Basic principles of density and specific gravity (SG) for liquids and gases
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  • Research the impact of phase changes on heat capacity calculations
  • Study the principles of thermal equilibrium in multi-phase systems
  • Explore the concept of heat of vaporization and its effects on heat capacity
  • Learn about the application of the first law of thermodynamics in heat capacity calculations
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Engineers, physicists, and chemists involved in thermal analysis, particularly those working with multi-phase systems involving liquids and gases.

Howy
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Hi,
I was woindering if anyone can help me on a problem I have been stuck on for a while now.

I have an equation to combine the heat capcity of oil and water, but I can't find an equation anywhere that combines the heat capacities for water oil and gas.

All i have is CpL = (qo(qo+qw))Cpo+(1-(qo/(qo+qw))Cpw

Does anyone know a formula for combing heat capacity of liquids and gases

Thanks, Howy
 
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Hi Howy, welcome to PF. This equation should work well for liquid-gas combinations too. It's simply saying the heat capacity contributions are independent and combined according to the (atomic) fraction of each material.
 
For a two-phase solution of water and steam, say at 100 degrees C, the heat capacity should include the heat of vaporization.
Bob S
 
Ah, good catch. I was assuming no phase change (which would apply to oil, water, and air around room temperature). Including a phase change, the heat capacity could be infinite for a solution combining a liquid with its own vapor (at constant pressure), for example. Howy, can you tell us what the gas is?
 
Wow,

Thanks for the hasty reply guys. Probably best to assume the following:

Water (pure)
Oil with a SG of 0.88 and a Cp of 1.7585 kj/kg.K
Gas (natural) with a Sg of 0.7 and a Cp of 5.5265 kj/kg.K
 
Last edited:
OK, for this particular system at thermal equilibrium, I don't see a problem with calculating the mass of each component and multiplying it by the material's specific heat capacity, and summing the results to estimate the system's heat capacity.
 
so do you think the following is acceptable?

Cp = (qo/qt)Cpo + (qw/qt)Cpw +(qg/qt)Cpg
 
What are the definition and units of the q's?
 
qo = quantity of oil being added
qw = quantity of water being added
qg = quantity of gas being added
qt = quantity of mixture

providing units are all the same i would have thought the units aren't important as it just a ratio
 
  • #10
OK, thanks for the clarification on definitions. This equation is going to give you a specific heat capacity, which isn't really meaningful, since the system isn't homogeneous. (For example, a sample random kilogram might contain all oil, all water, a mixture also containing some gas, etc.) It would be better to multiply the mass of each component by that material's specific heat capacity, then sum the results to obtain the system heat capacity (in J/K). Does this make sense?
 
  • #11
My understanding is, first work out each phase's mass flow rate

Wo = (densityofoil*qo)
Ww = (densityofwate*qw)
Wg = (densityofgas*qg)
WTotal = Wo + Ww + Wg



Then work out the ratio,

CpTotal = (Wo/WTotal)*Cpo + (Ww/WTotal)*Cpw + (Wg/WTotal)*Cpg
 

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