Is There a General Formula for this Partial Fraction Function?

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Hello,

Is there any general formula for the partial fraction of the following function:

\frac{1}{(ax_1+1)(ax_2+1)\cdots (ax_L+1)}

I can work for L=3, but it get involved for larger L!

Thanks in advance
 
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Ok... from what I've understood, you want write

\frac{1}{(ax_1+1)(ax_2+1)\cdots(ax_L+1)}

as

\frac{c_1}{ax_1+1}+\frac{c_2}{ax_2+1}+\cdots+\frac{c_L}{ax_L+1}

where the c's are constants. My question is, what is the variable the c's must be independent of? a or x?
 
coelho said:
Ok... from what I've understood, you want write

\frac{1}{(ax_1+1)(ax_2+1)\cdots(ax_L+1)}

as

\frac{c_1}{ax_1+1}+\frac{c_2}{ax_2+1}+\cdots+\frac{c_L}{ax_L+1}

where the c's are constants. My question is, what is the variable the c's must be independent of? a or x?

a is a constant, and x's are the variables.
 
coelho said:
Ok... from what I've understood, you want write

\frac{1}{(ax_1+1)(ax_2+1)\cdots(ax_L+1)}

as

\frac{c_1}{ax_1+1}+\frac{c_2}{ax_2+1}+\cdots+\frac{c_L}{ax_L+1}

where the c's are constants. My question is, what is the variable the c's must be independent of? a or x?

Problems involving partial fractions usually have one variable and many constants. From the appearance of your expression, I assume a is the variable and the x's are constants. In that case the c's will be determined by the x's.
 
mathman said:
Problems involving partial fractions usually have one variable and many constants. From the appearance of your expression, I assume a is the variable and the x's are constants. In that case the c's will be determined by the x's.

yes, right. a is the variable and x's are the constants. I got the general solution expression.

Thanks
 
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