Is this a differential equation?

johann1301
Messages
216
Reaction score
1
My textbook says that:

"A differential equation contains both the function and the derivative of the function"

and at the same time claims that y'=3x2 is a differential equation.

How can this be? The original function isn't part of the equation in this case?
 
Physics news on Phys.org
Yes it is. y'=3x2 is the same as y'+0y=3x2 (the coefficient of y is zero) and also the same as:
xy'=3y

But I think you need to take the textbook a little less seriously.
What they mean is that if g(x)=f(x,y,y',y''...) then g is a DE.
As you learn more the definition will get expanded to include more cases.
 
  • Like
Likes 1 person
It is a particularly easy differential equation- y is simply the anti-derivative of 3x^2. I would say the statement "A differential equation contains both the function and the derivative of the function" is at best misleading. The derivative of the function must appear explicitly in the equation. The function itself does not have to be explicitly in the equation.
 
  • Like
Likes 1 person
Thanks!
 
Thread 'Direction Fields and Isoclines'
I sketched the isoclines for $$ m=-1,0,1,2 $$. Since both $$ \frac{dy}{dx} $$ and $$ D_{y} \frac{dy}{dx} $$ are continuous on the square region R defined by $$ -4\leq x \leq 4, -4 \leq y \leq 4 $$ the existence and uniqueness theorem guarantees that if we pick a point in the interior that lies on an isocline there will be a unique differentiable function (solution) passing through that point. I understand that a solution exists but I unsure how to actually sketch it. For example, consider a...
Back
Top