Is this a trick question? more springs

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In summary, the problem involves a block with mass m being held against a compressed spring and then allowed to uncompress, giving the block a certain velocity. The block then slides to the right and up an incline at an angle of \theta degrees. The goal is to find the maximum height that the block reaches. All surfaces are frictionless, and the spring constant is k with an initial compression of x_0. The solution involves using the equation \frac{1}{2}kx_0 ^2 = mgh to calculate the maximum height. The angle may not be necessary, depending on whether the question is asking for vertical height gain or distance up the slope.
  • #1
flyingpig
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Homework Statement



A block with mass m is held against a compressed spring and then the spring is allowed to uncompress giving the block a velocity. The block slides to the right and then up an incline. Find the maximum height that the block reaches if the incline is [tex]\theta[/tex] degrees. All surfaces are frictionless, the spring constant is k and the initial spring compression is [tex]x_0[/tex].


The Attempt at a Solution



It says it gives the block a certain velocity, but that is after it releases right? So initally it still at rest. Also is the angle really necessary?

So really is it just

[tex]\frac{1}{2}kx_0 ^2 = mgh[/tex]
 
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  • #2
flyingpig said:

Homework Statement



A block with mass m is held against a compressed spring and then the spring is allowed to uncompress giving the block a velocity. The block slides to the right and then up an incline. Find the maximum height that the block reaches if the incline is [tex]\theta[/tex] degrees. All surfaces are frictionless, the spring constant is k and the initial spring compression is [tex]x_0[/tex].


The Attempt at a Solution



It says it gives the block a certain velocity, but that is after it releases right? So initally it still at rest. Also is the angle really necessary?

So really is it just

[tex]\frac{1}{2}kx_0 ^2 = mgh[/tex]

You are right about the velocity.
With regard to height, I would agree you don't need the angle if you are considering vertical height gain, which makes me wonder if they are expecting an answer like x metres up the slope, rather than a vertical height gain??
 

1. What is the purpose of "Is this a trick question? more springs?"

The purpose of "Is this a trick question? more springs" is to determine if a question is designed to deceive or confuse the person answering it, and if the use of more springs can make the question even more difficult to answer.

2. How can I tell if a question is a trick question?

There are a few things to look out for when trying to determine if a question is a trick question. These may include unclear or ambiguous wording, irrelevant information, or a hidden assumption. By using more springs, the question may become even more convoluted and difficult to decipher.

3. Is it fair to use more springs to make a question harder?

It depends on the context and purpose of the question. In some cases, using more springs may be intended to add an element of challenge or creativity to the question. However, in other cases, it may be considered unfair or manipulative. It's important to consider the intentions and impact of using more springs in a question.

4. Can using more springs in a question affect the answer?

Yes, using more springs in a question can potentially affect the answer. The added complexity and confusion may lead to incorrect or biased responses. It's important to consider the effects of using more springs on the overall validity and reliability of the question and its answers.

5. How can I create a fair and effective question without using more springs?

To create a fair and effective question, it's important to use clear and concise language, avoid loaded or leading questions, and consider the potential impact on different individuals or groups. It may also be helpful to have others review the question for any potential biases or unfairness. By avoiding the use of more springs, the question may be more straightforward and easier to answer for everyone.

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