Is This Complex Infinity Math Challenge Solvable?

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The discussion revolves around a math teaser involving a complex expression with infinity and imaginary numbers. The initial expression is simplified using limits, leading to an intermediate result of 8. However, participants debate the correctness of this answer, suggesting that the expression is indeterminate until applying L'Hospital's rule. A hint is provided to use polar forms of the complex numbers involved, ultimately leading to a revised answer of 2π. The conversation highlights the complexities of limits and the importance of proper mathematical techniques in solving such problems.
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Math Teaser!

Can you solve this?

\frac{4 \infty}{\sqrt{-1}} {(1+\sqrt{-1})^(1/\infty)-(1-\sqrt{-1})^(1/\infty)} [\tex]<br /> <br /> Edit: why this latex is not being generated? Anyway the &quot;expression&quot; is<br /> <br /> [(4*inf)/sqrt(-1)] * { [1+sqrt(-1)]^(1/inf) - [1-sqrt(-1)]^(1/inf) }<br /> <br /> where inf stands for infinity.
 
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Answer:
Taking the limit as N approaches infinity of

4N/i * [ (1+i)^(1/N) - (1-i)^(1/N) ]

which is:

4N/i * [ 1 + i(1/N) + o(N^-2) - 1 + i(1/N) + o(N^-2) ]

= 4N/i * [ 2i/N] + o(N^-1)

I get 8.

I'm not sure this is a brain teaser though.
 
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Sorry dude but I think its wrong.THe answer is something else.Btw it was a math teaser :)
 
Hint: The part in the parenthesis is a hyperbolic sine, and the result is indeterminate until you apply L'Hospital's to get the final answer.
 
I get zero as answer
 
Nooooo..,O.K. I shall give a hint .Use polar forms of (1+i) and (1-i).
Give it a try.
 
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That's a lot of hint. Here's what I get now:
2 * pi
I hope I didn't screw up somewhere.
 
Yeah its correct.
 
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