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Is this correct. Tangent lines.

  1. Mar 15, 2009 #1
    1. The problem statement, all variables and given/known data

    r(t) = sin t (i) + cos t (j) + t k


    Find the equation of the line tangent to r(t) at the point (0,1,0)

    If you plug in 0 into to for r(t), you get (0,1,0). Thus t must equal o.

    To find the vector of r' (t) or the derivative of r(t)

    this equals = < cos t, - sin t, 1 > which also equals cost (i) - sin t (j) + k


    So I find r'(0) = < 1,0,1>


    Then my equations are

    x= 1 t + 0

    y = 0t + 1

    z = 1t + 0


    x= 1t

    y = 1

    z = 1t
     
  2. jcsd
  3. Mar 16, 2009 #2

    HallsofIvy

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    Staff Emeritus
    Science Advisor

    Yes, that is correct.
     
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