- #1
Sashman15
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Divide using synthetic division (x^3-4x+1) / (x-5)
i got x^3 + 1^2 -9 Remainder: 46.
is it right?
i got x^3 + 1^2 -9 Remainder: 46.
is it right?
The quotient when dividing x^3-4x+1 by x-5 is x^2+5x+21.
To divide x^3-4x+1 by x-5, use long division or synthetic division. Set up the division problem with x-5 as the divisor and x^3-4x+1 as the dividend. Then, follow the steps of long division or synthetic division to find the quotient.
No, x-5 cannot be a factor of x^3-4x+1. When dividing x^3-4x+1 by x-5, there will be a remainder of 26. This means that x-5 is not a factor of x^3-4x+1.
The remainder when dividing x^3-4x+1 by x-5 is 26.
Yes, dividing x^3-4x+1 by x-5 is the same as finding the value of x^2+5x+21 when x=5. This is because the remainder is 26, which is the same as the value of x^2+5x+21 when x=5.