Divide x^3-4x+1 by x-5: Is it Right?

  • Thread starter Sashman15
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In summary, when dividing (x^3-4x+1) by (x-5) using synthetic division, the result should be a quadratic. None of the suggested answers are correct and the correct result can be found by setting x=5 in the polynomial (x^3-4x+1).
  • #1
Sashman15
7
0
Divide using synthetic division (x^3-4x+1) / (x-5)

i got x^3 + 1^2 -9 Remainder: 46.

is it right?
 
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  • #2
:O

Or is it 1x^3 - 9x^2 R: 46

?
 
  • #3
i think your first answer is correct looking quickly becasue there is a place holder for the x^2 term resulting in 0
 
  • #4
What am I missing?

You are using synthitic division to divide a cubic by a linear term. Should not your result be a quadratic? None of the suggestions made so far are correct.
 
  • #5
As integral said it is not right. Why don't you show your work?
 
  • #6
I might also point out that if you divide a polynomial, P(x), by the linear term x-a, the remainder is P(a). What do you get if you set x= 5 in
x3- 4x+ 1?
 

1. What is the quotient when dividing x^3-4x+1 by x-5?

The quotient when dividing x^3-4x+1 by x-5 is x^2+5x+21.

2. How do I divide x^3-4x+1 by x-5?

To divide x^3-4x+1 by x-5, use long division or synthetic division. Set up the division problem with x-5 as the divisor and x^3-4x+1 as the dividend. Then, follow the steps of long division or synthetic division to find the quotient.

3. Can x-5 be a factor of x^3-4x+1?

No, x-5 cannot be a factor of x^3-4x+1. When dividing x^3-4x+1 by x-5, there will be a remainder of 26. This means that x-5 is not a factor of x^3-4x+1.

4. What is the remainder when dividing x^3-4x+1 by x-5?

The remainder when dividing x^3-4x+1 by x-5 is 26.

5. Is dividing x^3-4x+1 by x-5 the same as finding the value of x^2+5x+21 when x=5?

Yes, dividing x^3-4x+1 by x-5 is the same as finding the value of x^2+5x+21 when x=5. This is because the remainder is 26, which is the same as the value of x^2+5x+21 when x=5.

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