Is This Flawed Proof by Induction Misusing the Principle?

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The discussion centers on a flawed proof by induction claiming that all horses are the same color. The main flaw identified is that the inductive step incorrectly assumes the case for n + 1 without addressing the specific case when n equals 2. Participants clarify that while the indexing of sets S', S'', and S may seem problematic, it does not invalidate the proof structure. The inductive hypothesis correctly asserts that all horses in the subsets S' and S'' are the same color, which is necessary for the proof to hold. Ultimately, the conversation enhances understanding of the nuances in applying the principle of induction correctly.
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At the end of this video lecture on the Principle of Induction, the teacher gives the following example of a flawed proof that misuses the principle.

Theorem. All horses are the same colour.

Proof. (By induction.)

Base case. In a set of one horse {h}, the principle clearly holds.

Inductive step. Suppose S = {h1,...,hn+1}, S' = {h1,...,hn}, S'' = {h2,...,hn+1} are sets of horses. Sets S' and S'' each have one horse fewer than S. h2 is an element of S' and of S''. Therefore all horses in S will have the same colour, in particular the same colour as h2.

End proof.


The explanation offered is that this proof fails because the inductive step assumes that n does not equal 2, and so isn't general enough.

Is there another flaw, namely that the proof treats S' and S'' as distinct sets of horses but has indexed them with the same natural number as each other? To use the principle of induction correctly, wouldn't we need to use distinct labels for distinct objects?

EDIT. Correction: It assumes n + 1 does not equal 2.
 
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No, what is done their is perfectly legitimate. If you have, say, four objects, labeled a, b, c, and d, you are justified into breaking the set {a, b, c, d} into the union of {a, b, c} and {b, c, d} and that is all that is done. The indexing is completely irrelevant to the proof.
 
Is the inductive hypothesis here not only that all the horses in S' are the same colour as each other, but also that all the horses in S'' are the same colour as each other? I'm guessing so, since the sets are indexed just by the number of elements they have. Then what the inductive step has to show is that these statements imply that all the horses in S are the same colour as each other.
 
Rasalhague said:
Is the inductive hypothesis here not only that all the horses in S' are the same colour as each other, but also that all the horses in S'' are the same colour as each other?
Certainly. The proof goes by induction on the number, say n, of horses. First it is shown that for n=1 it holds. Then the inductive hypothesis is that it holds for some n, i.e. that any set of n horses has the same color. This is then applied to the sets S and S'', which are both sets of n horses.
 
Okay, I think I get it now. Thank to you both for your help.
 
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