- #1

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- 19

r=cos(theta) and

r=sin(theta)

using a double integral.

I made the following:

[tex] 2\int^{\pi/2}_{\pi/4} \int^{\cos\theta}_0 r dr d\theta [/tex]

I multiplied by 2 because the area I have is only half of the total area to be found. Is this correct or am i doing something stupid?