Is this integration probelm right so far?

[Ravenatic20]

\int_{e}^{infinity} \frac{dx}{x \ln x} = \int_{e}^{infinity} \frac{1}{x \ln x} dx = \int_{e}^{infinity} \frac{1}{\ln x} d \ln x = ln|lnx| + Cevaluated from e to infinity

I think I know what I need to do next, I just want to make sure I'm good up to this point. Also, how do you put in an infinity sign, and evaluate sign? Thanks!

 

[Mystic998]

Infinity is just \infty. Dunno about the other.

Anyway, it looks correct to me.

 

[Pere Callahan]

Looks right. (And divergent)