Is This Ohm's Law Application Correct for an OP-AMP Circuit?

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SUMMARY

The discussion centers on the application of Ohm's Law (V = IR) in the context of an operational amplifier (OP-AMP) circuit. Participants clarify that the rectangular component in question is intended to represent a 1 F capacitor, particularly in differentiating OP-AMP configurations. The Laplace domain variable 's' is identified as crucial for understanding the impedance of reactive components. The conversation emphasizes the importance of clearly defined circuit components for accurate analysis.

PREREQUISITES
  • Understanding of Ohm's Law (V = IR)
  • Familiarity with operational amplifier (OP-AMP) configurations
  • Knowledge of Laplace transforms and their application in circuit analysis
  • Basic concepts of reactive components like capacitors and inductors
NEXT STEPS
  • Study the principles of differentiating and integrating OP-AMP circuits
  • Learn about Laplace transforms and their role in circuit analysis
  • Explore the characteristics and applications of capacitors in electrical circuits
  • Review the significance of feedback resistors in OP-AMP configurations
USEFUL FOR

Electrical engineering students, circuit designers, and anyone involved in analyzing or designing OP-AMP circuits will benefit from this discussion.

CoolDude420
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Homework Statement


Hi,

So I'm just curious whether or not the following statement is correct for the circuit shown. It's part of a bigger problem involving OP-AMPS, the part of the circuit shown is the upper loop connecting from the inverting to the output.

I was just having some doubts in my mind and wanted to confirm whether or not the equation i have written is correct.

ec61ee1761.png


Homework Equations


Ohms Law. V = IR.

The Attempt at a Solution



d66ba13ae1.png
 

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For the given component values it looks okay. Presumably the rectangular component is meant to represent a 1 F capacitor?
 
CoolDude420 said:

Homework Statement


Hi,

So I'm just curious whether or not the following statement is correct for the circuit shown. It's part of a bigger problem involving OP-AMPS, the part of the circuit shown is the upper loop connecting from the inverting to the output.

I was just having some doubts in my mind and wanted to confirm whether or not the equation i have written is correct.

View attachment 215789

Homework Equations


Ohms Law. V = IR.

The Attempt at a Solution



View attachment 215790
Interestingly gneill seems to understand your circuit and terminology, but I am struggling with it. However, any way I look at it I can't see the rectangular component as being a capacitor unless the OP AMP in question is a differentiating OP AMP and even then I would need to see a feedback resistor which is a key part of the the various voltage components. Since we are doing V = IR (or in this case I = V/R) I cannot understand this to be differentiating problem, so I would read that the rectangular component is a resistor with a value of 1/S but I am not able to determine what 'S' signifies. Also, if this is an integrating OP AMP, then there must be two resistor, R input and R feedback.
I may be just having a dumb day, bit I would like to see a full circuit, with the components correctly defined before I could comment on the correctness of the value terminology used in the equation.
 
Quandry said:
...so I would read that the rectangular component is a resistor with a value of 1/S but I am not able to determine what 'S' signifies.
The 's' is the Laplace domain "frequency" variable/operator (yes, it's both). Reactive components such as inductors and capacitors have impedances in the Laplace domain of the forms:

Inductance L: sL
Capacitance C: 1/(sC)

Laplace transforms are a very handy way to write and solve differential equations using simple algebra.
 
It is a sad day when you don't learn something new:smile: Although vaguely aware of Laplace transformations I have never used them.
For a differentiating OP AMP I would use the formula Iinput = C x dVinput/dt
 
gneill said:
For the given component values it looks okay. Presumably the rectangular component is meant to represent a 1 F capacitor?

Yes! That's exactly what it was meant to be. Thank you
 

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