ash64449 said:
well,i found this article and i find it simple to understand. But is this article totally correct?
Here is the link:
http://m.sparknotes.com/physics/specialrelativity/kinematics/section2.rhtml
By the way, the link appears to be to an online publishing site. A citation for this material is:
SparkNotes Editors. “SparkNote on Introduction to Special Relativity.” SparkNotes LLC. n.d.. http://www.sparknotes.com/physics/specialrelativity/intro/ (accessed April 13, 2013).
The name of the author is not given in any place on that site, as far as I could determine.
Regarding the correctness of the article:
I found a problem fairly early on. The development of time dilation looks reasonable up to and including the time ratio, t
B/t
A . That's the ratio of the time for one time interval of the "clock" as measured by a "stationary" observer, observer B, who measures the time as t
B and one time interval of the "clock" as measured by an observer on a moving train, observer A, who measures the time as t
A.
How does O
B, Observer B, actually determine t
B ?
The author of the article has O
A wave every time that the clock completes a cycle. Presumably, the train (along with O
A) is moving at a speed, v, which is a fairly large fraction of the speed light with respect to O
B. The author seems to imply that if O
B uses the time, Δt, that he observes as being the time between "seeing" one wave and the next wave --- that this Δt can be used as t
B. However, that doesn't work.
Let's suppose that O
B stands very close to the train track --- so we don't complicate matters via Pythagoras. The train moves a distance, v∙t
B, between successive waves by O
A . In order for O
B to determine t
B by observing the waves by O
A, O
B needs to consider the extra time it takes light to reach him from one wave to the next. (I presume O
B is using sight to observe O
A waving.)
As the train and O
A approach O
B, suppose O
A waves when the O
A is distance, d
1 from O
B, as measured in O
B's FoR (Frame of Reference). The next time O
A waves, the train will be v∙t
B closer to O
B than she was for the previous wave, so it takes light a time of (v∙t
B)/c less to reach O
B than light from the previous wave.
The time, Δt, between O
B's observation of successive waves of O
A is longer than t
B by an amount (v∙t
B)/c .
Therefore , t
B = Δt - (v∙t
B)/c .
When teaching relativity, I liked to use the word "infer" rather than the word "observe" when discussing time-dilation / length-contraction, as in: The stationary observer, O
B infers that the moving clock ticks at a slower rate than an identical clock which is stationary.
By the way: I do realize that there are several other ways for observer, O
B, obtain t
B from observer, O
A . The results will be equivalent.