Is this sufficient for a relation to be transitive

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The discussion centers on the relation R defined on the set S={0,1,2,3}, where (m,n) is in R if m + n = 3. It is argued that this relation is not transitive because there are no elements x, y, z in S such that both (x,y) and (y,z) exist in R. A vacuous argument for transitivity is proposed, suggesting that since no such elements exist, the transitive condition holds true by default. However, the example provided shows that while (0,3) and (3,0) are in R, (0,0) is not, confirming the lack of transitivity. The confusion about the uniqueness of the third number in the transitive relation is acknowledged and clarified.
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in the book I'm reading it gives a set S={0,1,2,3}, and it says that the relation R where (m,n) \in R if m + n = 3, m,n \in S.

it says that this relation isn't transitive, but couldn't you give a vacuous argument for transitivity.

more specifically there are no x,y,z s.t. (x,y) and (y,z) are elements of the S, therefore the statement
if (x,y) and (y,z) are in S then (x,z) is in S should be true, right?
 
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(0,3) and (3,0) are both in R, but (0,0) is not.
 
thanks, i don't know how i missed that. i must have had myself fooled that the 3rd number had to be unique from the first, when clearly it doesn't.
 
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