Is this vector calculus notation correct?

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My vector calculus is a bit rusty. Can anyone tell me if the following uses proper symbolism?

[tex] F &= \left[\begin{matrix}f_1(x_1,x_2) \\ f_2(x_1,x_2) \\ f_3(x_1,x_2) \end{matrix}\right] <br /> \qquad x = \left[\begin{matrix} x_1 \\ x_2 \end{matrix}\right] <br /> \qquad \frac{DF}{dx}&=<br /> \left[\begin{matrix}<br /> \rule{0pt}{3ex}\frac{\partial f_1}{\partial x_1} & \frac{\partial f_1}{\partial x_2} \\<br /> \rule{0pt}{3ex}\frac{\partial f_2}{\partial x_1} & \frac{\partial f_2}{\partial x_2} \\<br /> \rule{0pt}{3ex}\frac{\partial f_3}{\partial x_1} & \frac{\partial f_3}{\partial x_2}\end{matrix}\right][/tex]
 
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The first two look correct, but I don't think [tex]\frac{DF}{dx}[/tex] is a common notation. I would use just [tex]DF[/tex] or maybe [tex]\frac{\partial f}{\partial x}[/tex].

Edit: http://en.wikipedia.org/wiki/Jacobian_matrix" uses the notation [tex]J_F[/tex].
 
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Im very turned around in vector calc! I have the equation 4y2 -4z2=5y/x-4x2 and I need to convert it from rectangular to cylindrical coordinates. Could someone explain this better than my professor?
 
Hi, Jon89bon!

I had a bit of vector calculus in my first semester at the university and I'm not sure if what I paste here is truly correct, so it would need an overview from a supervisor :)

Here's what we do:

1. we transform the equation: 4y^2 -4z^2=5y/x-4x^2 into

(4y^2 -4z^2+4x^2)x-5y=0=:f(x,y,z) and set a func. f equal to it.

2. As f is a SCALAR field, we could use the transformations:

(x,y,z)=(rcos(a),rsin(a),z), where r^2=x^2+y^2 and a is the angle of rotation around the z-axisremark: if you're good at algebra, you could skip the first step :)IMPORTANT: I think, this transformation does not apply to vector fields (when f is a vector), but I need an approval for that statement from s.o. else :)all the best, marin
 
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Thanks I will work with this and see what I come up with!

Jon89bon