Isomorphism of A(Zn) and Zn/{0}: A Proof

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SUMMARY

The discussion focuses on proving the isomorphism between A(Zn) and Zn/{0}, as well as A(Z) and Z2. It establishes that A(Zn) consists of automorphisms of the cyclic group Zn, which are represented by non-zero elements of Zn, thus confirming A(Zn) is isomorphic to Zn/{0}. Additionally, it concludes that A(Z), the automorphism group of integers, is isomorphic to Z2, as it only contains two automorphisms: the identity and the negation function.

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  • Understanding of group theory concepts, specifically automorphisms
  • Familiarity with cyclic groups, particularly Zn
  • Knowledge of bijective functions and their properties
  • Basic comprehension of isomorphisms in algebra
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Homework Statement



Recall that given a group G, we defined A(G) to be the set of all isomorphisms from G to itself; you proved that A(G) is a group under composition.
(a) Prove that A(Zn) is isomorphic to Zn/{0}
(b) Prove that A(Z) is isomorphic to Z2

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The Attempt at a Solution

 
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There aren't very many automorphisms of Z->Z. In fact, I think there is only two of them. For the other question, I'm not really sure what Z_n/{0} means. Can you explain?
 
Can you figure out the sets A(Zn) and A(Z)?
The identity function is one that should come to mind.
Take a general function on Z by f(x)=bx for some b in Z. What values can b take on so that f(x) is a bijection?
 

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