Isothermal titration calorimetry

[Quickdry135]

Homework Statement

Using isothermal titration calorimetry, you calculate \DeltaH^{o}_{bind} (= -5000 cal/mol) for a protein-ligand binding reaction at 25°C. You then perform a separate assay in which you measure equilibrium ligand binding at two different temperatures:

L_{0} (nM) Ceq (nM) at 25°C Ceq (nM) at 37°C
0.01 :: 0.007 :: 0.006
0.03 :: 0.021 :: 0.017
0.1 ;: 0.070 :: 0.058
0.3 :: 0.197 ;: 0.166
1 :: 0.537 :: 0.439
3 ;: 0.830 :: 0.778
10 :: 0.943 :: 0.930
30 :: 1.002 :: 0.964
100 :: 0.981 :: 1.009

What is \DeltaS^{0}_{bind} at 37C

Homework Equations

\DeltaG^{0}=RTlnK_{D}

\DeltaG=\DeltaG^{0} + RTln[L]_{eq}/[P]_{eq}[L]_{eq}

\DeltaG=\DeltaH-T\DeltaS

The Attempt at a Solution

I can find K_{d} graphically and therefore find \DeltaG^{0} to be -12300.1 cal. At the same temperature, \DeltaG^{0}=\DeltaG at 25C, so i can find \DeltaS at 25C. But I don't know how this helps me find \DeltaS^{0}_{bind} at 37C or if this helps me at all.

thanks for any help or direction

 

[Quickdry135]

never mind, I think i figured it out using the van't hoff equation to find delta H at 37C since I can find the different Kds and am given the different temperatures.