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Isotropic antenna Transmit and Receive power

  1. Jul 19, 2012 #1
    1. The problem statement, all variables and given/known data
    Plot and compare the path loss (dB) for the free-space and plane-Earth models at 800MHz vs distance on a logarithmic scale for distances from 1m to 40Km. Assume that the antennas are isotropic and have a height of 10m


    2. Relevant equations

    Free space: [itex]P_R=\frac{P_T G_T G_R}{L_P}[/itex]

    Plane Earth: [itex]P_R=P_TG_TG_R(\frac{h_Th_R}{R^2})^2[/itex]

    Two isotropic antennas separated by a distance [itex]R\epsilon[1m,40km][/itex] at frequency [itex]f=800MHz[/itex].




    3. The attempt at a solution
    Isotropic antennae have [itex]G_T=G_R=1[/itex]. So That simplifies [itex]P_R=\frac{P_T G_T G_R}{L_P}[/itex] = [itex]P_R=\frac{P_T}{L_P}[/itex]
    [itex]L_P=(\frac{R4\pi}{\lambda})^2[/itex].

    I'm solving the question for 1m for the free space model, then once I have that, plotting it is easy in Excel.

    I'm stuck on finding [itex]P_T[/itex]. I tried deriving an equation for [itex]P_T[/itex]by substituting [itex]L_P=(\frac{R4\pi}{\lambda})^2[/itex] into [itex]P_R=\frac{P_T}{L_P}[/itex] but that lead me nowhere. At least I don't know what the answer means.

    Here's what happened.

    [itex]P_R=\frac{P_T}{R^24\pi}A_e[/itex]
    [itex]P_R=\frac{P_T}{L_P}[/itex]
    [itex]L_P=(\frac{R4\pi}{\lambda})^2[/itex]
    [itex]\frac{P_T}{R^24\pi}A_e=\frac{P_T}{(\frac{R4\pi}{λ})^2}[/itex]
    Then a bunch of cancellation on both sides and finally
    [itex]Ae 4\pi = \lambda^2[/itex]

    Help! I don't know how to find [itex]P_T[/itex]
     
  2. jcsd
  3. Jul 19, 2012 #2

    marcusl

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    What is Lp? How does it relate to what you are asked for?
     
  4. Jul 19, 2012 #3
    For reliable communication, Lp is the minimum signal level required at the receiving antenna. It's a ratio of [itex]\frac{P_T (mW)}{P_R(mW)}[/itex]. The distance [itex]R = \frac{\lambda\sqrt{L_P}}{4\pi}[/itex]. Rearranging and solving for [itex]L_P = (\frac{4R\pi}{\lambda})^2[/itex] implies the loss is related to the distance separated by the antennas as well as the wavelength of the transmitted signal.

    Thanks for pointing that out. I can now solve my problem :D
     
  5. Jul 19, 2012 #4

    marcusl

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    You're welcome!
     
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