IV Characteristics of Simple Diode Circuits

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SUMMARY

The discussion focuses on the IV characteristic curves of simple diode circuits, specifically configurations involving diodes and resistors in series and parallel. Key scenarios include a diode and resistor in series, a diode and resistor in parallel, and a combination of these configurations with a reversed diode. The analysis reveals that when a diode conducts, it maintains approximately 0.6 to 0.7 volts across it, and the current through the resistor can be calculated using Ohm's Law. A practical example is provided, demonstrating how to derive current values at different input voltages.

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  • Understanding of diode operation and characteristics
  • Familiarity with Ohm's Law
  • Basic knowledge of circuit analysis
  • Ability to graph IV characteristics
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Master J
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I'm trying to figure out what the IV characteristic curves are of some simple diode circuits.

A) Diode and resistor in series.

B) Diode and resistor in parallel

C) Diode and resistor in parallel, and this combo in series with another diode reversed wrt. first diode.

Its been a while since I've looked at diodes...Im not certain which way to approach this.
Any help on getting me in the right direction would be very much appreciated!

Thanks!
 
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You could consider what happens when the diode is fully conducting. It then has about 0.7 volts across it and any resistors will be obeying Ohm's Law.
EDIT.
Suppose you put a diode and a resistor in series and assume a diode with 0.6 volts across it when it is conducting, and a 100 ohm resistor.

Input volts 0.1
Volts across diode 0.1
Voltage across resistor = 0
Current in resistor = 0

Keep doing this in steps of 0.1 volt

Input volts 1
Volts across diode 0.6 V
Voltage across resistor = 0.4 V
Current in resistor = 0.4 V / 100 ohms = 4 mA
Current in diode = 4 mA

If you do this, you can then draw a graph of the results.
 
Last edited:

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