Jacobian Calculation for Transformation (x, y) to (u, v)

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SUMMARY

The discussion focuses on calculating the Jacobian of the transformation from (x, y) to (u, v) where u = x² + y² and v = x + y. To find the Jacobian d(x, y)/d(u, v), one can either solve for x and y as functions of u and v, use implicit differentiation to determine the partial derivatives, or take the reciprocal of the Jacobian d(u, v)/d(x, y). The matrix for the Jacobian d(u, v)/d(x, y) is represented as det|{(∂u/∂x, ∂u/∂y)(∂v/∂x, ∂v/∂y)}.

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franky2727
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calculate the jacobian d(x,y)/d(u,v) of the transformation u=x2+y2
v=x+y

for this do i first have to calculate the jacobian d(u,v)/d(x,y) then do 1over the answer? because i would assume the matrix to be det|{(dudx,dudy)(dvdx,dvdy)} but with (u,v) on top i cannot get this
 
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franky2727 said:
calculate the jacobian d(x,y)/d(u,v) of the transformation u=x2+y2
v=x+y

for this do i first have to calculate the jacobian d(u,v)/d(x,y) then do 1over the answer? because i would assume the matrix to be det|{(dudx,dudy)(dvdx,dvdy)} but with (u,v) on top i cannot get this

You can do any of three things:
1) Solve for x and y as functions of u and v.
2) Use implicit differentiation to find [itex]\partial x/\partial u[/itex], [itex]\partial y/\partial u[/itex], [itex]\partial x/\partial v[/itex], and [itex]\partial y/\partial v[/itex].
3) Take the reciprocal of d(u,v)/d(x,y).
 

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