Jaynes-Cummings Density Operator Evolution

Click For Summary
SUMMARY

The discussion focuses on the evolution of the density operator for two-level atoms interacting with fields, specifically in the context of Dicke Superradiance. The Optical Bloch Equations, as presented in Loudon's book, describe the time evolution of the density operator matrix elements, while the Lindblad master equation accounts for decoherence and dissipation in open quantum systems. The key distinction is that the Lindblad equation incorporates spontaneous emission effects, which are absent in the Optical Bloch Equations. This makes the Lindblad equation essential for modeling realistic quantum systems that experience environmental interactions.

PREREQUISITES
  • Understanding of Optical Bloch Equations
  • Familiarity with the Lindblad master equation
  • Knowledge of quantum mechanics, particularly two-level systems
  • Concept of decoherence and dissipation in quantum systems
NEXT STEPS
  • Study the derivation and applications of the Lindblad master equation
  • Explore the implications of decoherence in quantum computing
  • Investigate the role of spontaneous emission in quantum optics
  • Learn about the differences between closed and open quantum systems
USEFUL FOR

Quantum physicists, researchers in quantum optics, and students studying open quantum systems will benefit from this discussion, particularly those interested in the dynamics of two-level atoms and their interactions with fields.

stephen8686
Messages
42
Reaction score
5
TL;DR
I do not understand the optical bloch equations and the Lindblad master equation. Are they not stating the same thing?
I am studying two level atoms interacting with fields in order to study Dicke Superradiance.
From Loudon's book, the Optical Bloch Equations for a two level atom interacting with a field say (with rotating wave approx):

$$\frac{d\rho_{22}}{dt}=- \frac{d\rho_{11}}{dt} = -\frac{1}{2} iV(e^{i\Delta \omega t}\rho_{12}-e^{-i\Delta \omega t}\rho_{21})$$
and
$$ \frac{d\rho_{12}}{dt}= \frac{d\rho_{21}^*}{dt} = \frac{1}{2}iVe^{-i\Delta\omega t}(\rho_{11}-\rho_{22}) $$

I have also seen the Lindblad master equation, given by:
$$ \frac{d}{dt}\hat{\rho} = \frac{1}{i\hbar} [\hat{H},\hat{\rho}] + \kappa \hat{L}[\hat{a}]\hat{\rho} + \sum^N_{j=1} \gamma \hat{L}[\hat{\sigma}_j^-]\hat{\rho} + \frac{1}{2T_2}\hat{L}[\hat{\sigma}^z_j]\hat{\rho}+ w\hat{L}[\hat{\sigma}_j^+]\hat{\rho} $$

So if the optical bloch equations already give the time evolution for all of the elements of the density operator matrix, why is the master equation important? Is it just easier to implement because it is one equation rather than two coupled ones, or is there a more important difference between these two approaches?
 
Physics news on Phys.org
I think your first set of equations doesn't contain spontaneous emission while the Lindblad equation does. Compare your notes with this:
https://www.ifsc.usp.br/~strontium/Teaching/Material2020-1 SFI5814 Atomicamolecular/Anderson - Monograph - Bloch equations.pdf

Generally speaking, the Lindblad equation is used for open quantum systems and includes terms which lead to decoherence and dissipation. If you start with a pure state, this kind of time evolution usually leads to a mixed state. This can't happen under the unitary dynamics of isolated quantum systems which is represented by the first term of the RHS of the Lindblad equation you have written (the commutator term).
 

Similar threads

  • · Replies 2 ·
Replies
2
Views
1K
  • · Replies 1 ·
Replies
1
Views
1K
  • · Replies 14 ·
Replies
14
Views
3K
  • · Replies 16 ·
Replies
16
Views
3K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 9 ·
Replies
9
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 3 ·
Replies
3
Views
1K
  • · Replies 2 ·
Replies
2
Views
2K