JK Master-Slave Flip-Flop timing diagram

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SUMMARY

The discussion focuses on the timing diagram of the JK Master-Slave Flip-Flop (FF), emphasizing the operational differences between the master and slave components. It is established that the master operates on the rising edge of the clock pulse while the slave responds to the falling edge. Key insights include the necessity for input stabilization several nanoseconds before the clock's falling edge to ensure accurate output. Additionally, the participants highlight that the JK inputs should not change coincident with the clock's falling edge to avoid timing issues.

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  • Understanding of JK Flip-Flop operation
  • Knowledge of clock pulse timing in digital circuits
  • Familiarity with timing diagrams and waveform analysis
  • Basic concepts of level-triggered versus edge-triggered circuits
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  • Study the timing requirements for JK Master-Slave Flip-Flops in detail
  • Learn about setup and hold times in digital circuits
  • Explore the differences between level-triggered and edge-triggered flip-flops
  • Review circuit schematics for JK Flip-Flops to understand gating arrangements
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Electronics students, digital circuit designers, and engineers working with sequential logic circuits will benefit from this discussion, particularly those focusing on flip-flop timing and operation.

JasonHathaway
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Homework Statement


Draw the output Q of the JK Master-Slave Flip-Flop

Homework Equations


Master works at the rising edge, while and the Slave works at the falling edge.

The Attempt at a Solution



http://s13.postimg.org/j5ldpmw9i/20150109_095656.jpg
 
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JasonHathaway said:

Homework Statement


Draw the output Q of the JK Master-Slave Flip-Flop

Homework Equations


Master works at the rising edge, while and the Slave works at the falling edge.

The Attempt at a Solution



http://s13.postimg.org/j5ldpmw9i/20150109_095656.jpg

Could you post the schematic for the J/K M/S flipflop you are using for this problem please? Thanks. :)

EDIT -- And were you given the J & K waveforms as part of the problem statement?
 
EDIT waveforms look okay

On the rising edge of clock pulse #1 (CP#1), your figure shows J=0 & K=1
subsequently on the falling edge of CP#1 this sets Q to 1.

That is not what I was expecting of a JK FF.
Are you sure that is right?
 
Last edited:
The first part is OK. (Q is not defined by the inputs before clk 1 falling edge). The master is at J=1, K=0 which on that edge is transferred to the slave, so Q1 = 1 upon the falling edge of clk1.

The J input at the falling edge of clk3 should not coincide with that clock edge. There needs to be a minimum setup time on J before that edge occurs. However, assuming J is still high when the clk3 edge occurs, that Q wavform is also correct (toggle action).

The same problem obtains at the falling edge of clk5. What did the master latch?

Bottom line: inputs must be stabilized at least several ns before a clock falling edge. This is the only timing requirement for a master-slave FF. Timing of the inputs is not important for the rising edge of any clock pulse since the master FF output is immaterial until the clk drops.
 
Last edited:
After closer scrutiny, I agree with rude man. JasonHathaway's sketch of waveforms is correct. (I'd forgotten that for the Master, it's not "edge triggered" as such. Level triggered would be more accurate.) The question of JK inputs changing coincident with the fall of the clock pulse is also a caution that should be heeded.

However, none of us is correct if the gating arrangement in the linked .gif is used, because it interposes an inversion between the Master and the Slave.
 
Last edited:
NascentOxygen said:
After closer scrutiny, I agree with rude man. JasonHathaway's sketch of waveforms is correct. (I'd forgotten that for the Master, it's not "edge triggered" as such. Level triggered would be more accurate.) The question of JK inputs changing coincident with the fall of the clock pulse is also a caution that should be heeded.

However, none of us is correct if the gating arrangement in the linked .gif is used, because it interposes an inversion between the Master and the Slave.
Probably a typo on the master FF outputs. Should look same as the slave.
In any case, the OP's schematic is inadequate. The circuit should be shown in terms of gates; see attached.
 

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