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BasharTeg
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Homework Statement
I am new to the whole GR concept so I just would like to know if what I did is correct or utterly ******** (and if so, why).
I have to find all Killing Vectors to a given metric (1) using equation (2). (2) leads to 3 partial differential equations which I used to calculate them.
Homework Equations
(1) [tex] ds^2=-dt^2 +dx^2 [/tex]
(2) [tex]L_{\xi}g_{\mu \nu}=\xi^{\alpha}\partial_{\alpha}g_{\mu \nu}+g_{\mu \alpha}\partial_{\nu}\xi^{\alpha}+g_{\alpha \nu}\partial_{\mu}\xi^{\alpha}=0[/tex]
The Attempt at a Solution
I used equation to solve the three equations [tex]L _\xi g_{tt}=0[/tex], [tex]L _\xi g_{xx}=0[/tex] & [tex]L _\xi g_{tx}=0[/tex].
That leads to
[tex]\partial_t \xi^t=0[/tex]
[tex]\partial_x \xi^x=0[/tex]
[tex]\partial_t \xi^x=\partial_x \xi^t[/tex]
the first 2 lead to
[tex]\xi^t=f(x)[/tex]
[tex]\xi^x=g(t)[/tex]
and inserting that into the last equation shows that this one has to be equal to a constant since you can completely separate the x and t depention. So with integration I get:
[tex]\xi^x=g(t)=At+B[/tex]
[tex]\xi^t=f(x)=Ax+C[/tex]
So I have 3 constants and the solution:
[tex]\xi=A \binom{t}{x} + B \binom{0}{1}+C\binom{1}{0}[/tex]
and therefore those 3 vectors are the 3 linear independant Killing vectors.
Is that correct?
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