Kc = 1.88 for 2HI(g) ↔ H2(g) + I2(g)

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Discussion Overview

The discussion revolves around calculating the equilibrium constant (Kc) for the reaction H2(g) + I2(g) ↔ 2HI(g), given the Kc value for the reverse reaction HI(g) ↔ 1/2 H2(g) + 1/2 I2(g) is 1.37. Participants explore the mathematical relationships between these Kc values and the implications of reversing and doubling the reaction.

Discussion Character

  • Homework-related
  • Mathematical reasoning

Main Points Raised

  • One participant states the Kc for the reaction HI(g) ↔ 1/2 H2(g) + 1/2 I2(g) is 1.37 and seeks to find Kc for the reverse reaction.
  • Another participant presents the equations for Kc and suggests finding a relation between Kc values for the two reactions.
  • Some participants express uncertainty about how to mathematically manipulate the Kc values given the reactions are reversed and doubled.
  • There is a suggestion to square the first Kc equation and multiply it by the second to derive the desired Kc value.

Areas of Agreement / Disagreement

Participants generally agree on the need to relate the Kc values mathematically, but there is uncertainty regarding the specific mathematical steps required to achieve this.

Contextual Notes

Participants have not fully resolved the mathematical approach to relate the Kc values, and there are assumptions about the manipulation of equilibrium constants that remain unexamined.

Madelin Pierce
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Homework Statement


Kc = 1.37 for HI(g) ↔ 1/2 H2(g) + 1/2 I2(g). What is Kc (to 3 decimal places) for H2(g) + I2(g) ↔ 2HI(g)?

Homework Equations


Kc= Products/Reactants, Ice Tables

The Attempt at a Solution


I tried an ice table, but I’m not sure what to do with the Kc value I’m given when I have to another Kc value
 
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$$K_{c_1} = 1.37 = \dfrac{[H_2]^{1/2} [I_2]^{1/2}}{[HI]}$$ and $$K_{c_2} = \dfrac{[HI]^2}{[H_2][I_2]}$$ Can you find a relation between ##K_{c_1}## and ##K_{c_2}##?
 
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I know the reaction reversed and doubled. But I don’t know how to solve for Kc mathematically with this set-up.
 
Madelin Pierce said:
But I don’t know how to solve for Kc mathematically with this set-up.
What maths are you referring to? If you can find ##K_{c_2}## in terms of ##K_{c_1}##, then can't you find ##K_{c_2}##?
 
Madelin Pierce said:
I know the reaction reversed and doubled. But I don’t know how to solve for Kc mathematically with this set-up.
What do you get if you square @Wrichik Basu's first equation, and then multiply it by his second equation.
 

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