Kennedy-Thorndike Experiment

  • #1
unscientific
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Homework Statement


lfdxh.jpg


In this problem i take the maximum relative velocity of ether wind to be (u + v) where they both complement each other..



The Attempt at a Solution



Not sure how they ended up with a '4uv' term..
 

Answers and Replies

  • #2
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Would appreciate any help..
 
  • #3
TSny
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In this problem i take the maximum relative velocity of ether wind to be (u + v) where they both complement each other..
Good. What would the minimum relative velocity be during the day? δ is the change in Δt(c/λ) in going from maximum to minimum relative velocity.
 
Last edited:
  • #4
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Good. What would the minimum relative velocity be during the day? δ is the change in Δt(c/λ) in going from maximum to minimum relative velocity.

I got very close to the answer, just that my term had a '2uv' instead of a '4uv'..
 
  • #5
TSny
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Did you calculate Δt for both the maximum and minimum velocity relative to the ether and then take the difference between these two Δt's? Also note the initial factor of 2 in the expression for Δt.
 
  • #6
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Did you calculate Δt for both the maximum and minimum velocity relative to the ether and then take the difference between these two Δt's? Also note the initial factor of 2 in the expression for Δt.

Yes, but there is a factor of (1/2) beside the square...
 
  • #7
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Ah, I see my mistake now..
 

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