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Kennedy-Thorndike Experiment

  1. Sep 27, 2012 #1
    1. The problem statement, all variables and given/known data
    lfdxh.jpg

    In this problem i take the maximum relative velocity of ether wind to be (u + v) where they both complement each other..



    3. The attempt at a solution

    Not sure how they ended up with a '4uv' term..
     
  2. jcsd
  3. Sep 28, 2012 #2
    Would appreciate any help..
     
  4. Sep 28, 2012 #3

    TSny

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    Good. What would the minimum relative velocity be during the day? δ is the change in Δt(c/λ) in going from maximum to minimum relative velocity.
     
    Last edited: Sep 28, 2012
  5. Sep 28, 2012 #4
    I got very close to the answer, just that my term had a '2uv' instead of a '4uv'..
     
  6. Sep 28, 2012 #5

    TSny

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    Did you calculate Δt for both the maximum and minimum velocity relative to the ether and then take the difference between these two Δt's? Also note the initial factor of 2 in the expression for Δt.
     
  7. Sep 29, 2012 #6
    Yes, but there is a factor of (1/2) beside the square...
     
  8. Sep 29, 2012 #7
    Ah, I see my mistake now..
     
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