Kernel of Matrix Homework Solution

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To find the kernel of the given matrix, it is essential to solve the equation Ax = 0. The matrix has a zero column, which can lead to confusion, but the kernel is determined by the linear combinations of the columns. The solution reveals that the kernel is spanned by the unit vector e1, which is [1, 0, 0]. The initial difficulty stemmed from overthinking the simplicity of the problem, but ultimately, the straightforward approach confirmed the kernel's solution. Understanding the role of zero columns is crucial in determining the kernel effectively.
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Homework Statement


Find the kernel of \left( \begin{array}{ccc}<br /> 0 &amp; 1 &amp; 0 \\<br /> 0 &amp; 0 &amp; 1 \\<br /> 0 &amp; 0 &amp; 0 \end{array} \right)\

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The Attempt at a Solution



I know how to find the kernel of a matrix that has numbers in all of the columns, but I think that since this matrix has a zero vector in the first column it's throwing me off. I know the answer is the unit vector e1, but I don't know why.

I know that
imA = span(\left( \begin{array}{ccc}<br /> 1 \\<br /> 0 \\<br /> 0 \end{array} \right)\, \left( \begin{array}{ccc}<br /> 0 \\<br /> 1 \\<br /> 0 \end{array} \right)\)

And I know that the kernel is what makes Ax = 0. But I can't figure it out for some reason, while I can easily get the more complicated problems. Maybe it's too simple and I'm over-thinking it?
 
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So, if the matrix had nonzero entries, how would you approach the problem then?? And what's different about this case??
 
Yes, turns out I was overthinking it. I set it up like a normal problem and for some reason stopped because it looked strange. Then I continued with it and got the unit vector [1,0,0].
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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