Kinematic Problem: Finding Initial Height of a Thrown Baseball in 2.53 Seconds

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Homework Statement



Baseball is throwing upwards with initial velocity as 12m/s. Total time it took to reach ground is 2.53 seconds. Find the initial height where baseball was thrown.

Homework Equations


The Attempt at a Solution



Find d

t=2.53
Vo=12

0=d+Vo*t-4.9t^2
0=d+12*2.53-4.9t^2
d=4.9*2.53^2-12*2.53
d=1.00

is this right?
 
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What if the ball was launched at angle, let's say 30 degrees?