mattstjean
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Hi, I am also having trouble with the hockey puck question.
A hockey puck rebounds from a board as shown in my diagram. The puck is in contact with the board for 2.5 ms. Determine avg acceleration of the puck over the interval.
Vi = 26 m/s Vf = 21 m/s
I tried the cosine law but I keep getting 44 m/s and not 18. I don't understand how you guys got 18 m/s. I've plugged it in at least 100 times as
<br /> v_t = \sqrt{v_1^2 + v_2^2 - 2(v_1)(v_2)cos136}<br /> = \sqrt{26^2 + 21^2 - 2(26)(21)cos136}<br /> =44<br /> =
Because that wasn't working I then tried Vector Components and I can't get that to work either. I did:
<br /> V_x = V_B sin \theta + (-V_A cos \beta ) <br /> = 21 sin(22) - 26 cos(22)<br /> =-16<br />
and
<br /> V_y = V_B cos \theta + (-V_A sin \beta ) <br /> = 21 (cos22) + 26(sin22)<br /> = 29 <br />
I then tried to figure out
<br /> \Delta V ^2= \Delta V_x ^2 + \Delta V_y^2 <br /> = sqrt{16^2 + 29^2}<br /> = 33<br />
Using that I tried to get the average acceleration by:
<br /> A_av = \Delta V / \Delta T<br /> <br /> A_av = 33 / 2.5x10^-3<br /> A_av = 13.2x10^3<br />
and to find the angle I tried to do :
<br /> \phi = tan^-1 = 16/29<br /> \phi = 29degrees<br />
However, the answer in my book says that the average acceleration is 7.3x10^3 [7.5degrees North of West]
Any help would be amazingly appreciated. Thanks.
A hockey puck rebounds from a board as shown in my diagram. The puck is in contact with the board for 2.5 ms. Determine avg acceleration of the puck over the interval.
Vi = 26 m/s Vf = 21 m/s
I tried the cosine law but I keep getting 44 m/s and not 18. I don't understand how you guys got 18 m/s. I've plugged it in at least 100 times as
<br /> v_t = \sqrt{v_1^2 + v_2^2 - 2(v_1)(v_2)cos136}<br /> = \sqrt{26^2 + 21^2 - 2(26)(21)cos136}<br /> =44<br /> =
Because that wasn't working I then tried Vector Components and I can't get that to work either. I did:
<br /> V_x = V_B sin \theta + (-V_A cos \beta ) <br /> = 21 sin(22) - 26 cos(22)<br /> =-16<br />
and
<br /> V_y = V_B cos \theta + (-V_A sin \beta ) <br /> = 21 (cos22) + 26(sin22)<br /> = 29 <br />
I then tried to figure out
<br /> \Delta V ^2= \Delta V_x ^2 + \Delta V_y^2 <br /> = sqrt{16^2 + 29^2}<br /> = 33<br />
Using that I tried to get the average acceleration by:
<br /> A_av = \Delta V / \Delta T<br /> <br /> A_av = 33 / 2.5x10^-3<br /> A_av = 13.2x10^3<br />
and to find the angle I tried to do :
<br /> \phi = tan^-1 = 16/29<br /> \phi = 29degrees<br />
However, the answer in my book says that the average acceleration is 7.3x10^3 [7.5degrees North of West]
Any help would be amazingly appreciated. Thanks.