Kinematics Problem but not enough information?

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Homework Help Overview

The problem involves kinematics, specifically analyzing the motion of a commuter train traveling between two stations that are 1.42 km apart. The train accelerates and then brakes, and the task is to find the minimum travel time and the time spent accelerating.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the relationship between acceleration, time, and distance, questioning how to apply kinematic equations given the changing acceleration. There is uncertainty about how to correctly set up the equations for the two phases of motion.

Discussion Status

Some participants have provided hints and equations to help clarify the problem, while others express confusion about the application of these hints. There is ongoing exploration of the relationships between the variables involved, but no consensus has been reached on a complete solution.

Contextual Notes

Participants note the challenge of not being able to use the total distance directly due to the change in acceleration, and there are indications of frustration with external systems not accepting their answers.

intriqet
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Hi Guys, its my first post here and I have a feeling that I'll be using this forum as a resource. Maybe once I learn enough I'll be able to contribute in solving other peoples' homework problems.
Anyway, to the problem:

Homework Statement



A commuter train travels between two downtown stations. Because the stations are only 1.42 km apart, the train never reaches its maximum possible cruising speed. During rush hour the engineer minimizes the travel interval deltaT between the two stations by accelerating for a time interval deltaT1 at a1 = .100m/s^2 and then immediately braking with acceleration a2 = -.390 m/s^2 for a time interval deltaT2. Find the minimum time interval of travel deltaT and the time interval deltaT1.

So we are given:
A1 = .1 m/s^2 A2 = -.390 m/s^2
V i1 = 0 m/s Vf2=0m/s
delta X = 1420 m

Homework Equations



kinematics equations



The Attempt at a Solution



I feel like I'm overthinking this one and am overlooking a relatively simple solution. I know can't use 1420 as deltaX because the train does not accelerate at one rate for the entire distance. Now I only have 2 variables for the first half of the problem.


Please any hints will greatly help asap. Thanks!
 
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In the first half, vf = a1T1, in the second half vi = a2T2.
vf = vi = v.
Hence a1T1 = a2 T2. Find T1
Next x1 = 0.5*a1*T1^2...(1)
x2 = 0.5*a2*T2^2...(2)
Sustitute the value of T1 in eq.(1) and add it to eq.(2). (x1 + x2) is know. Find T2.
 
Thanks very much for the prompt reply but I am not quite sure I understand.

Based on your hint, I plugged in a1T1 for Vf in Vf^2-Vi^2 = 2AxDeltaX. leaving me with T1 = sqrt(2DeltaX).

Please tell me if I'm going the correct direction and please excuse the fact that I'm a complete DA.
 
intriqet said:
Thanks very much for the prompt reply but I am not quite sure I understand.

Based on your hint, I plugged in a1T1 for Vf in Vf^2-Vi^2 = 2AxDeltaX. leaving me with T1 = sqrt(2DeltaX).

Please tell me if I'm going the correct direction and please excuse the fact that I'm a complete DA.
You have to find T1 as
T1 = a2*T2/a1.Put it in equation (1)
 
Thanks to your help I was able to derive some answers! The answer I got for t2 is 50.1 s and t1 195 s. So the entire trip was 245 s long. Is this correct?
 
Your answers are correct.
 
Blurg! Webassign will not take my answers. Any other suggestions?
 
intriqet said:
bump
Have you entered delta T and deltaT1?
 
Yessiree. I think it's webassign but I guess I can skip this problem it's for extra credit.
 

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