Kinetic energy and momentum p=mv

[SciSteve]

So I have a physics problem that has the normal equation KE=1/2mv^2 and KE=p^2/2m and i have no idea how they get the second equation is it a derivative or something with calculus? any helps greatly appreciated thanks in advance.

 

[ZapperZ]

p=mv.

Use that in the first equation.

Zz.

 

[Math Jeans]

Here is how it is derived:

p=mv

KE=(1/2)mv^2

KE=(1/2)mv*v (mv=p)

KE=(1/2)pv (v=p/m)

KE=(1/2)p*(p/m)

KE=(1/2)*(p^2/m)

KE=p^2/2m


Hope that helped.

 

[ZapperZ]

We usually try to get the person to do or discover the answer for him/herself, rather than spoonfeeding the answer completely.

Zz.