Kinetic Energy in water and the rate carried across each square meter

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SUMMARY

The discussion focuses on calculating the kinetic energy in a cubic meter of seawater and the rate of energy transfer across a square meter due to an ocean current flowing at 2.5 m/s. The density of seawater is established at 1030 kg/m³. The kinetic energy (KE) can be calculated using the formula KE = 0.5 * m * v², where 'm' is the mass and 'v' is the velocity. The mass of 1 m³ of seawater is 1030 kg, leading to a kinetic energy of 3,212.5 Joules per cubic meter and a power extraction limit of 8,025 Watts per square meter.

PREREQUISITES
  • Understanding of kinetic energy formulas
  • Basic knowledge of fluid dynamics
  • Familiarity with the properties of seawater
  • Ability to perform unit conversions and calculations
NEXT STEPS
  • Learn about fluid dynamics and energy transfer in fluids
  • Study the principles of hydropower generation
  • Explore the effects of varying seawater density on kinetic energy calculations
  • Investigate real-world applications of kinetic energy extraction from ocean currents
USEFUL FOR

Students in physics, engineers in renewable energy, and researchers focused on ocean energy systems will benefit from this discussion.

annie05
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1. Consider an ocean current flowing at 2.5m/s
a) How much kinetic energy is contained in a cubic volume of water that measures 1m on each side? The density of seawater is about 1030kg/m3
b) If the flow is perpendicular to one of the cube faces, what is the rate at which the current carries kinetic energy across each square metre? Your answer gives an upper limit for the power that could be extracted from the flow, although it is an unrealistic limit because you’d have to stop the entire flow

2. I am not sure of which equations to use


3. No attempted solution
 
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