Kinetic Friction of jet powered skiis

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SUMMARY

Joe, weighing 80 kg, utilizes jet powered skis with a thrust of 186 N and a coefficient of kinetic friction of 0.1 on snow. After 8 seconds of operation, Joe reaches a top speed of 10.76 m/s before the skis run out of fuel. The frictional force acting against him is calculated, allowing for the determination of the distance he travels while coasting to a stop after fuel depletion. The analysis confirms the importance of understanding both thrust and friction in calculating motion on snow.

PREREQUISITES
  • Understanding of Newton's Second Law of Motion
  • Knowledge of frictional force calculations
  • Familiarity with kinematic equations
  • Basic principles of jet propulsion mechanics
NEXT STEPS
  • Study the derivation of Newton's Second Law in various contexts
  • Learn about calculating frictional forces in different materials
  • Explore kinematic equations for motion with constant acceleration
  • Investigate the principles of jet propulsion and its applications in sports
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Physics students, mechanical engineers, and anyone interested in the dynamics of motion involving thrust and friction, particularly in sports applications.

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Homework Statement


Joe, whose mass is 80kg, takes off across level snow in his jet powered skiis. The skiis have a thrust of 186N and a coefficient of kinetic friction on snow of 0.1. Unfortunately, the skiis run out of fuel after only 8 s. What is Joe's top speed? How far has Joe traveled when he finally coasts to a stop?


Homework Equations





The Attempt at a Solution

 
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Please show some work.

Joe's mass (80 kg) is subjected to a force 186 N, but experiences a retarding (friction) force. The coefficient of friction is 0.1.

So determine the acceleration, from which speed can be determined at the end of 8 s.

Then with that speed, Joe decelerates with friction, so determine how far based on the maximum speed (magnitude of velocity) through the distance where he stops.

Refer to this - http://hyperphysics.phy-astr.gsu.edu/hbase/mot.html
 
I got his top speed to be 10.76 m/s by using the frictional force in the equation. I just don't know which equation to use from there.
 

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