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Kinetic Friction of ride down a ramp

  1. Jul 23, 2009 #1
    1. The problem statement, all variables and given/known data

    A 28.0 kg seal at an amusement park slides down a ramp into the pool below. The top of the ramp is 1.80 m higher than the surface of the water and the ramp is inclined at an angle of 30.0° above the horizontal. The seal reaches the water with a speed of 4.90 m/s.

    What is the work done by kinetic friction?

    2. Relevant equations

    mgh

    K = 1/2mv^2

    3. The attempt at a solution

    initial energy = mgh = 493.92

    final energy = Kf = 1/2mv^2 = 336.14

    If the initial was 493.92 and the final was 336.14 then I would assume there was a loss of 157.78, but that wasn't the right answer. Any help?
     
  2. jcsd
  3. Jul 23, 2009 #2

    turin

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    Homework Helper

    I believe that you did this problem correctly. The only two things that I can think of are significant figures and minus sign conventions. I would call the work negative.
     
  4. Jul 23, 2009 #3

    rock.freak667

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    Homework Helper

    my calculator does not give that, how did you get that?

    But mgh= 1/2mv2 +Wf does look correctly applied.
     
  5. Jul 23, 2009 #4
    Whoops, silly mistake. You're right, I just had to put a negative sign on the work of friction. Thanks.
     
  6. Jul 23, 2009 #5
    Ok so the answer was -157.78 J and in order to find the coefficient of kinetic friction, uk, I thought it would be to simply divide by (mg) but I guess it isn't that simple in this scenario. How would I determine uk?
     
  7. Jul 23, 2009 #6

    jgens

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    Gold Member

    You would need to find the friction force first. You have that Wf = Ff * d and Ff = uk * FN
     
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