A 28.0 kg seal at an amusement park slides down a ramp into the pool below. The top of the ramp is 1.80 m higher than the surface of the water and the ramp is inclined at an angle of 30.0° above the horizontal. The seal reaches the water with a speed of 4.90 m/s.
What is the work done by kinetic friction?
K = 1/2mv^2
The Attempt at a Solution
initial energy = mgh = 493.92
final energy = Kf = 1/2mv^2 = 336.14
If the initial was 493.92 and the final was 336.14 then I would assume there was a loss of 157.78, but that wasn't the right answer. Any help?