Kinetics after car left the cliff.

  • Thread starter Thread starter dorian_stokes
  • Start date Start date
  • Tags Tags
    Car Kinetics
Click For Summary
SUMMARY

The discussion focuses on calculating the kinetic energy of a car with a mass of 1515 kg that is pushed off a cliff of height 26 m, landing 14 m away from the base. The key to solving this problem lies in determining the velocity of the car at the moment it leaves the cliff. Using the kinematic equation V^2 = v_o^2 - 2(g)(x_f - x_i), the calculated velocity is 22.6 m/s. This velocity is essential for calculating the kinetic energy, which is given by the formula KE = 0.5 * m * v^2.

PREREQUISITES
  • Understanding of kinematic equations
  • Knowledge of gravitational acceleration (g = 9.81 m/s²)
  • Familiarity with the concept of kinetic energy
  • Basic algebra for solving equations
NEXT STEPS
  • Learn how to apply kinematic equations in projectile motion
  • Study the derivation and application of the kinetic energy formula
  • Explore the effects of air resistance on falling objects
  • Investigate real-world applications of kinetic energy in automotive safety
USEFUL FOR

Students studying physics, particularly those focusing on mechanics and kinematics, as well as educators looking for practical examples of energy calculations in motion.

dorian_stokes
Messages
24
Reaction score
0

Homework Statement


A car of mass m = 1515 kg is pushed off a cliff of height h = 26 m. If the car lands a distance of 14 m from the base of the cliff, what was the kinetic energy of the car the instant after it left the cliff?



Homework Equations





The Attempt at a Solution

Don't even know where to begin because this is a kenetics problem.
 
Physics news on Phys.org
You need to know the velocity of the car to calculate it's kenitic energy. How can you find the velocity of the car the instant it left the cliff.

Hint: You'll need to use the kenimatic equations you already learned.
 
It said to find the kinetic energy after it left the cliff and not the velocity. I calculated the velocity to be 22.6m/s using the V^2=v_o^2-2(g)(x_f-x_i). Is this wrong?
 

Similar threads

Replies
2
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
Replies
1
Views
3K
Replies
1
Views
2K
  • · Replies 1 ·
Replies
1
Views
1K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 6 ·
Replies
6
Views
3K
  • · Replies 1 ·
Replies
1
Views
3K
  • · Replies 31 ·
2
Replies
31
Views
4K