Kronecker Delta: A Relativity and Tensor Explanation

  • Context: Graduate 
  • Thread starter Thread starter Terilien
  • Start date Start date
  • Tags Tags
    Delta
Join the discussion
Registration is free. Ask a follow-up in this thread, or start your own.
5 replies · 7K views
Terilien
Messages
140
Reaction score
0
I keep seeing this come up in relativity and tensor resources but I have no idea wht the heck it means. Could someone explain it to me?
 
Physics news on Phys.org
Terilien said:
I keep seeing this come up in relativity and tensor resources but I have no idea wht the heck it means. Could someone explain it to me?

The Kronecker delta is a function of two integers. If the integers are the same then the value of the function is 1. Otherwise it is zero. This function can be represented as a matrix. The notation for this function is [itex]\delta[/itex]ij.

Pete
 
pmb_phy said:
The Kronecker delta is a function of two integers. If the integers are the same then the value of the function is 1. Otherwise it is zero. This function can be represented as a matrix. The notation for this function is [itex]\delta[/itex]ij.

Pete


Why is it important in tensor analysis?
 
Example from relativity. Let the coordinates of an event be [itex]\left\{x^0 , x^1 , x^2 , x^3 \right\}.[/itex] Then, using the summation convention of summing over repeated indices,

[tex]x^\mu \delta_{\mu \nu} = x^0 \delta_{0 \nu} + x^1 \delta_{1 \nu} + x^2 \delta_{2 \nu} + x^3 \delta_{3 \nu}.[/tex]

Since the Kronecker delta is zero unless both indices are equal, only one of the terms in the above sum survives. We don't know which one, but we know it's the one that has [itex]\nu[/itex] as its first index. Therefore, the sum equals [itex]x^\nu .[/itex]
 
Last edited:
Terilien said:
Why is it important in tensor analysis?
because it's a metric tensor of euclidean space? dunno. the "importance" asigned to things by different people is quite biased.