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Lagrange constraint mechanics problem

  1. Oct 25, 2010 #1
    [​IMG]

    Just a simple question. I can see that for this to work I need:

    Trot = 1/5 ma2(thetaDOT + phiDOT)2

    Just can't work out what phi has to do with rotational kinetic energy. I would have thought it would need to be simply the same thing but without the phiDOT term.
     
    Last edited: Oct 25, 2010
  2. jcsd
  3. Oct 25, 2010 #2

    diazona

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    [itex]\theta[/itex] is the angular position of an identified point on the smaller sphere, measured with respect to the line joining the centers of the two spheres, right? Note that not only does [itex]\theta[/itex] change with time, but so does the orientation of that joining line, so you need to take that into account as well. That's where the [tex]\dot\phi[/tex] comes from.
     
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