Laplace Transform of Systems of ODEs with variable coefficients

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SUMMARY

The discussion focuses on solving a system of ordinary differential equations (ODEs) with variable coefficients using the Laplace Transform. The equations presented are EQ1: y1''*t + y1'*t + y2 = 0 and EQ2: y2''*t + y2'*t + y1 = 0, with initial conditions y1(0)=0, y1'(0)=0, y2(0)=0, and y2'(0)=0. The solution approach involves adding and subtracting the equations to define new variables z1 and z2, where z1 = (y1 + y2) and z2 = (y1 - y2), simplifying the integration process.

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  • Understanding of Laplace Transforms and their application to differential equations.
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Students and professionals in mathematics, engineering, and physics who are dealing with systems of ordinary differential equations, particularly those requiring the application of Laplace Transforms for solutions.

physics19921
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Homework Statement


Say you have:

EQ1: y1''*t+y1'*t+y2=0

and

EQ2: y2''*t+y2'*t+y1=0

y1(0)=0,y1'(0)=0,y2(0)=0,y2'(0)=0


Homework Equations





The Attempt at a Solution



I can get it so far, but having both y1 and y2 really gives me fits:

Eq1: Y1(-2s-1)+dY1/ds(-s2-s)=-Y2

Eq2: Y2(-2s-1)+dY2/ds(-s2-s)=-Y1

I try to shift it around to be dY1/Y1 = (-2s-1)/(-s2-s)-Y2/Y1(-s2-s)

But then I just don't know to do the integrations given you have both Ys. I just can't separate them.

Any help would be appreciated.
 
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Welcome to PF, physics19921! :smile:

You can't separate the Ys?
So don't.
Add them, and subtract them respectively.

That is, add the 2 equations and solve for z1=(y1+y2).
Then subtract the 2 equations and solve for z2=(y1-y2).
Finally combine the solutions...
 

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