Laplace Transforms of Discontinuous functions

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SUMMARY

The Laplace transform of the function (t − 1)^2u(t − 1) is derived using the formula L{f(t-a)u(t-a)}(s) = e^-as F(s). In this case, f(t) is identified as t^2, which is crucial for applying the transform correctly. The confusion arises from the interpretation of the function's argument; while (t-1)^2 is the expression, the function f(t) itself is defined as t^2. This distinction is essential for accurate computation of the Laplace transform.

PREREQUISITES
  • Understanding of Laplace transforms and their properties
  • Familiarity with unit step functions, specifically u(t-a)
  • Basic knowledge of function notation and transformations
  • Experience with algebraic manipulation of functions
NEXT STEPS
  • Study the derivation and applications of the Laplace transform for piecewise functions
  • Learn about the properties of the unit step function u(t-a)
  • Explore examples of Laplace transforms involving discontinuous functions
  • Investigate the implications of shifting functions in the Laplace domain
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Students and professionals in engineering, mathematics, and physics who are working with Laplace transforms, particularly those dealing with discontinuous functions and their applications in system analysis.

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Homework Statement



(t − 1)^2u(t − 1) Find the Laplace transform.

Homework Equations



L{f(t-a)u(t-a)}(s) = e^-as F(s)

The Attempt at a Solution



The solution manual says take f(t) = t^2, I don't see why? Why is f(t) not (t-1)^2?
 
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Because t-1 is in the argument of f. If f(t-1)=(t-1)^2, I would say f(t)=t^2.
 

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