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Laplace Transforms of Discontinuous functions

  1. Nov 9, 2007 #1
    1. The problem statement, all variables and given/known data

    (t − 1)^2u(t − 1) Find the Laplace transform.

    2. Relevant equations

    L{f(t-a)u(t-a)}(s) = e^-as F(s)

    3. The attempt at a solution

    The solution manual says take f(t) = t^2, I dont see why? Why is f(t) not (t-1)^2?
  2. jcsd
  3. Nov 9, 2007 #2


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    Science Advisor
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    Because t-1 is in the argument of f. If f(t-1)=(t-1)^2, I would say f(t)=t^2.
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