Laplace's Equation Boundary Problem

Join the discussion
Ask a follow-up here, or get your own question answered by working scientists, mathematicians and engineers — people, not an autocomplete.
Real named experts · corrections over time · the nuance an AI answer skips
1 reply · 3K views
sqrt(-1)
Messages
17
Reaction score
0

Homework Statement



I have a two part question, the first part involves solving Laplace's equation

[tex] u_{xx} + u_{yy} = 0[/tex]

for the boundary conditions
[tex] u_x(0,y) = u_x(2,y) = 0[/tex]

[tex] u(x,0) = 0[/tex]

[tex] u(x,1) = \sin(\pi x)[/tex]
for
[tex]0 < x < 2, 0 < y < 1[/tex].

The second part now states a new boundary problem for the same equation, involving the square area defined on [tex]0 < x < 1, 0 < y < 1[/tex]. This time we have
[tex] u_x(0,y) = u(1,y) = 0[/tex]

[tex] u(x,0) = 0[/tex]

[tex] u(x,1) = 2\sin(\pi x)[/tex]
The question asks me to use the solution from the first boundary problem to solve this problem directly (using a theorem/principle).

Homework Equations


The Attempt at a Solution



I have solved the first part using the standard method of separation of variables but I'm rather puzzled as to what this mystery theorem/principle is that can allow me to take my solution from the first problem and apply it directly to the second boundary problem :frown:
 
Physics news on Phys.org