Hypatio
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I am trying to derive part of the navier-stokes equations. Consider the following link:
http://www.gps.caltech.edu/~cdp/Desktop/Navier-Stokes%20Eqn.pdf
Equation 1, without the lambda term, is given in vector form in Equation 3 as \eta\nabla^2\mathbf{u}. However, when I try to get this from Eq. 1, I get 2\eta\nabla^2\mathbf{u}. I am getting 2\eta because
\eta\left(\frac{\partial u_i}{\partial x_j}+\frac{\partial u_j}{\partial x_i}\right)=\eta(\nabla \mathbf{u}+\nabla \mathbf{u}^T)=2\eta\nabla \mathbf{u}
and then the taking the divergence gives \nabla\cdot 2\eta\nabla\mathbf{u}=2\eta\nabla^2\mathbf{u} for constant viscosity \eta
I suspect that my second step in the first line is wrong. But I don't get it.
Thanks in advance.
http://www.gps.caltech.edu/~cdp/Desktop/Navier-Stokes%20Eqn.pdf
Equation 1, without the lambda term, is given in vector form in Equation 3 as \eta\nabla^2\mathbf{u}. However, when I try to get this from Eq. 1, I get 2\eta\nabla^2\mathbf{u}. I am getting 2\eta because
\eta\left(\frac{\partial u_i}{\partial x_j}+\frac{\partial u_j}{\partial x_i}\right)=\eta(\nabla \mathbf{u}+\nabla \mathbf{u}^T)=2\eta\nabla \mathbf{u}
and then the taking the divergence gives \nabla\cdot 2\eta\nabla\mathbf{u}=2\eta\nabla^2\mathbf{u} for constant viscosity \eta
I suspect that my second step in the first line is wrong. But I don't get it.
Thanks in advance.