Large deviation principle and Fibonacci sequence

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SUMMARY

The discussion centers on proving the limit involving the Fibonacci sequence and the large deviation principle. Specifically, it addresses the limit as n approaches infinity of (1/n)log[A((1+sqrt(5))/2)^n + B((1-sqrt(5))/2)^n], which equals (1+sqrt(5))/2. The participant attempted to use L'Hôpital's Rule but encountered confusion regarding the presence of logarithms in their differentiation process. Clarification is sought on the correct application of L'Hôpital's Rule in this context.

PREREQUISITES
  • Understanding of limits in calculus
  • Familiarity with L'Hôpital's Rule
  • Knowledge of logarithmic differentiation
  • Basic concepts of the Fibonacci sequence and its relation to the golden ratio
NEXT STEPS
  • Study the application of L'Hôpital's Rule in limit problems
  • Research logarithmic differentiation techniques
  • Explore the mathematical properties of the golden ratio, specifically (1+sqrt(5))/2
  • Investigate the large deviation principle in probability theory
USEFUL FOR

Students and researchers in mathematics, particularly those focusing on calculus, limits, and the Fibonacci sequence, will benefit from this discussion.

dyh
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Homework Statement



A>0, B can be any number

Homework Equations



To show that

lim(n->∞) (1/n)log[A((1+sqrt(5))/2)^n +B((1-sqrt(5))/2)^n] = (1+sqrt(5))/2

The Attempt at a Solution



I used Lhopital's Rule to solve this and got
log((1+sqrt(5))/2)

So, I don't know what is wrong.
If you guys know how to prove this one, please let me know.
Thanks a lot
 
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If you used L'Hopital's principle, how do you still have a logarithm?
 
Because if I differentiate A*(1+sqrt(5))^n with respect to n

then I would get

A*log(1+sqrt(5))*(1+sqrt(5))^n
 

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